2(3x^2+1)=4x

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Solution for 2(3x^2+1)=4x equation: 



2(3x^2+1)=4x

We move all terms to the left:

2(3x^2+1)-(4x)=0

We add all the numbers together, and all the variables

-4x+2(3x^2+1)=0

We multiply parentheses

6x^2-4x+2=0

a = 6; b = -4; c = +2;
Δ = b2-4ac
Δ = -42-4·6·2
Δ = -32
Delta is less than zero, so there is no solution for the equation

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